I've created and sent an email using:
import randomalphabet=list('0123456789')for i in range(26): alphabet.append(chr(ord('a') + i)) alphabet.append(chr(ord('A') + i))def gen_random_string(length=30): return ''.join([alphabet[random.randint(0, len(alphabet) - 1)] for i in range(length)])from email.message import EmailMessageimport emailimport smtplibmsg = EmailMessage()msg['From'] = my_emailmsg['To'] = other_emailmsg.set_content(text)msg['Message-ID'] = email.utils.make_msgid(idstring=gen_random_string(), domain="MY-DOMAIN")s = smtplib.SMTP('smtp.gmail.com', '587')s.starttls()s.login(credentials.login, credentials.password)s.send_message(msg)s.quit()However, Gmail replaced it:
Message-ID: <5e7f5e01.1c69fb81.47373.ca02@mx.google.com>X-Google-Original-Message-ID: <158540544125.4261.11383854704184591387.n6h3EeqHMnoMCVVSkrgbCqlSyCeTfv@MY-DOMAIN>According to https://groups.google.com/forum/#!topic/comp.mail.sendmail/gkRdBwka4iw:
Yes, gmail seems to only overwrite the Message ID if you submit it in a wrong format.
In general, I want to get a message-id of the arbitrary sent message (not only from Gmail accounts). I do not understand if the problem is with the python email library or Gmail.
[UPD]: without idstring everything works fine.